Question

sin 30°- cos 60° urgent​

Answer 1

$\huge\sin(30) = \frac{1}{2} \\ \\ \huge \: \cos(60) = \frac{1}{2}$

$\\ \\ \huge\bf \sin(30) - \cos(60) = \\ \\ \huge\bf= \frac{1}{2} - \frac{1}{2} = 0$