Question

sin 45 grade:(cos30grade-tg30grade)=


Multumesc!

Answer 1

sin 45° = $\frac{\sqrt{2} }{2}$

cos 30° = $\frac{\sqrt{3} }{2}$

tg 30° = $\frac{\sqrt{3} }{3}$

tot ce trb sa faci este sa inlocuiesti si faci calculul!

bafta!

Answer 2

sin 45°=$\frac{1}{2}$

cos 30°=$\frac{ \sqrt{3} }{2}$

tg 30°=$\frac{ \sqrt{3} }{3}$

$\frac{1}{2} \div ( \frac{ \sqrt{3} }{2} - \frac{ \sqrt{3} }{3} ) = \\ = \frac{1}{2} \div \frac{ \sqrt{3} }{2} - \frac{1}{2} \div \frac{ \sqrt{3} }{3} = \\ = \frac{1}{2} \times \frac{2}{ \sqrt{3} } - \frac{1}{2} \times \frac{ \sqrt{3} }{3} = \\ = \frac{1}{ \sqrt{3} } - \frac{ \sqrt{3} }{6} = \\ = \frac{ \sqrt{3} }{3} - \frac{ \sqrt{3} }{6} = \\ = \frac{2 \sqrt{3} }{6} - \frac{ \sqrt{3} }{6} = \\ = \frac{ \sqrt{3} }{6}$