Question

sin(arccos 5/13)
AJUTOR!!​

Answer 1

$\sin( arccos (\frac{5}{13} ) ) = \sqrt{1 - (\frac{5}{13} }) ^{2} = \sqrt{1 - \frac{25}{169} } = \sqrt{ \frac{144}{169} } = \frac{ \sqrt{144} }{ \sqrt{169} } = \frac{ \sqrt{12 ^{2} } }{\sqrt{13^{2} } } = \frac{12}{13}$