Question

Sistemele 3x + 4y =-6 5x+7y =-31 si 4x+2y=6 2x-y=1 prin metoda substitutiei

Answer 1

Răspuns:

3x+4y=-6~x=(-6-4y)/3

5x+7y=-31~5*(-6-4y)/3+7y=-31

~-30-20y+21y=-93

~y=-93+30=-63

~x=(-6-4*-63)/3=(-6+252)/3=246/3=82

Si

4x+2y=6

2x-y=1~y=2x-1

~4x+4x-2=6~8x=8~x=1

x=1~y=2-1=1