Question

solutia ecuatiei (x-3)²-2(x-4)(x+4)=1-(x-5)(x+4) este

Answer 1

$1).(x-3)^2-2(x-4)(x+4)=1-(x-5)(x+4) \\ x^2-2*x*3+3^2-2(x^2-16)=1-(x^2+4x-5x-20) \\ x^2-6x+9-2x^2+32=1-x^2-4x+5x+20 \\ x^2-2x^2+x^2-6x+4x-5x=1+20-9-32 \\ -7x=-20 \\ x= \frac{20}{7} \\ 2).E=(3x-5)^2-(2x+1)^2 \\ E=(3x-5-2x-1)(3x-5+2x+1) \\ E=(x-6)(5x-4)$