Question

Solutia ecuatiei (x-3)²-2(x-4)(x+4)=1-(x-5)(x+4) este

Answer 1

x²-2•x•3+3²-2•x²-4x-4x-16=1-x²-4x-5x-20
x²-6x+9-2x²-8x-16=x²-9x-19
-x²-14x+7=x²-9x-19
-x²-14x+7+x²-9x-19=0
-23x-12=0
-23x=12
x=-12/23
S={-12/23}

Answer 2

(x-3)(x-3)-2(x-4)(x+4)=1-(x-5)(x+4)

(x²-3x-3x+9)-(2x-8)(x+4)=1-(x-5)(x+4)

(x²-6x+9)-(2x²+8x-8x-32)=1-(x²+4x-5x-20)

-x²-6x-23 = 1-x²-x-20

-x²-6x-23-1+x²+x+20=0

-5x-4=0

-5x=4 ==>x=4/-5  ===> S={4/-5}