Question

Solutia ecuatiei:x²+5x=0

Answer 1

D=b^2-4ac=>D=25; radical(D)=5;
x1=-(b+radical(D) )2a=>x1=(-5+5)/2=0
x2=-(b-radical(D) )2a=>x2=(-5-5)/2=-10/2=-5;
ecuatia are 2 solutii: -5 si 0;