Question

solutia, numar intreg , a ecuatiei 2xpatrat +7x+3=0

Answer 1

$2x^2+7x+3=0 \\\\ a=2 \\ b=7 \\ c=3 \\\\ \Delta= 7^2-4*2*3= 49-24\to\boxed{25} \\\\ x_1;x_2= \frac{-7 + / - \sqrt{25}}{2*2}= \frac{-7 + / - 5}{4} \\\\ x_1= \frac{-7+5}{4}= -\frac{2}{4}\to - \frac{1}{2} \\\\ x_2= \frac{-7-5}{4} = -\frac{12}{4}\to -3 \\\\\\ 2x^2+7x+3=0 \\\\ (x^{(2}+\frac{1}{2})(x+3)=0 \\\\ ( 2x+1)(x+3)=0\\\\\boxed{\boxed{S=\{-3\in Q\}}}}$