Question

Solutiile din intervalul [0, 2pi] ale ecuatiei sin(2x+pi/6) = -1/2 ​

Answer 1

Răspuns:

$x = \frac{\pi}{2} \\ x = \frac{5\pi}{6} \\ x = \frac{3\pi}{2} \\ x = \frac{11\pi}{6}$

Explicație pas cu pas:

$2x + \frac{\pi}{6} = \frac{7\pi}{6} + 2\pi \: n \\ = > x = \pi \: n + \frac{\pi}{2} \\ 2x + \frac{\pi}{6} = \frac{11\pi}{6} + 2\pi \: n \\ = > x = \pi \: n + \frac{5\pi}{6} \\ x = \frac{\pi}{2} \\ x = \frac{5\pi}{6} \\ x = \frac{3\pi}{2} \\ x = \frac{11\pi}{6}$