Question

Soriei tereltatel operatiilor ca puteri ale unor numere intregi: 22 by (-3) (-3) c) (-4).(-4): 4) e) 7.7.(-7) 1 x x x x x h) 36:32: i) (-4) : (-4) 1 (-20% (-20% (-20% k) [(-28]: ) 1) (5) my (-377 ) m) [(-787 0[(-1) 24-3] " [(-2)*(+3)')': ) (-2):2 1( 19 [-3. (+787 u) (a².6² (²)​

Answer 1

Răspuns:

Explicație pas cu pas:

a) 2^3×2^4=2^7

b) (-3)^2×(-3)^6= (-3)^8

c) (-4)×(-4)^2= (-4)^3

d) 5^2×5^4×5^6= 5^12

e) 7×7×(-7)= (-7)^3

f) X×X^2×X^3×X^4×X^5= X^15

g) (-2)^4:(-2)^3= (-2)

h) 3^6:3^2= 3^4

i) (-4)^10:(-4)^7= (-4)^3

j) (-20)^10:(-20)^5:(-20)^5=(-20)^5:(-20)^5=1

k) [(2)^2]^3= 2^6

l) (5^1)^0=1

m) [(-3)^5]^2=(-3)^10

n) [(-7)^3]^5 = (-7)^15

o) [(-1)^7]^4=(-1)^28

p) [2^2×(-3)^3]^2= 2^4×(-3)^6

q) [(-2)×(+3)^2]^3=(-2)^3×(+3)^6

r) (-2)^7×2^5=-(2)^12

s) [(+6)(-2)(-3)]^2=(6^2)^2=(6)^4

t) [-3×(+7)^2]^0=1

u) (a^2×b^2×c^2)^4= (a^8×b^8×c^8)