Question

Stabileste cantitatea de magneziu aflata in - in 11,6g hidroxid de magneziu
-in 48g oxid de magneziu
- in 16,8g carbonat de magneziu
-in 29,6g azotat de magneziu
Macar 2 sa faceti cu ecplicatii si dau coroana celui mai bun raspun

Answer 1

11,6 g Mg(OH)2                  M Mg(OH)2 =24 +2.16 +2=58
                                          58gMg(OH)2-------24 g Mg
48 g Mg O                         11,6gMg( OH)2------x

16,8 g Mg CO3                  x=11,6.24:58=4,8 g Mg

29,6 g Mg( NO3)2
                                          MMg O=24+16=40

                                         40 g MgO---------24gMg
                                        48g MgO-----------Y
                                          Y=48.24:40=28,8 g Mg


                                     MMg CO3=24+12+3.16=84
                              84gMgCO3----------24 g Mg
                            16,8 gMgCO3---------Z
                                Z=16,8.24:84=4,8 g Mg


                              MMg(NO3)2 =24+2.14+6.16=148

                            148 g Mg(NO3)2---------24 g Mg
                          29,6 g Mg( NO3)2------------ a

                            a=29,6.24:148=4,8 g Mg


?g Mg