Question

stie cineva cat da 1 la puterea 2017+ 2017 la puterea 1×0 la puterea 2017×2017 la puterea 0 × 32

Answer 1

 

$\displaystyle\bf\\1^{2017}+2017^1\times0^{2017}\times2017^0\times32=\\\\=1+\underbrace{2017\times0\times1\times32}_{=~0}= 1+0 = \boxed{\bf1}$

 

Answer 2

Răspuns:

1

Explicație pas cu pas:

1+2017×0×1×32=

=1+0

=1