Question

Stie cineva cum se rezolva ?​

Answer 1

lim x->3, x< 3 f(x) = lim x->3, x > 3 f(x)

lim x-> 3, x< 3 (x-2)k+7 = lim x->3, x> 3 (8-x)k²-5kx+10

=> (3-2)k+7 = (8-3)k²-5•3k+10

=> k+7 = 5k²-15k+10

=> 5k²-16k+3 = 0

Delta = 16²-4•5•3 = 186 = 14²

=> k1,2 = (16±14)/10

=> k1 = 1/5, k2 = 3