Question

Știe cineva cum se rezolva?

Answer 1

Răspuns:

Explicație pas cu pas:

$a) ~log_2128=log_22^6=6*1=6\\ ~log_{\frac{1}{2} }4=log_{2^{-1}}2^2=\frac{1}{-1}*2*log_22=-2*1=-2.\\log_{0,1}10=log_{\frac{1}{10} }10=log_{10^{-1}}10=\frac{1}{-1}*log_{10}10=-1*1=-1.\\b)~log_210-log_215+log_248=log_2\frac{10*48}{15}=log_232=log_22^5=5*log_22=5*1=5.\\c)~log_315+log_310-log_350=log_3\frac{15*10}{50}=log_33=1.\\ d)~\frac{log_518-log_52}{log_53}=\frac{log_5\frac{18}{2} }{log_52}=\frac{log_59}{log_53}=\frac{log_53^2}{log_53}=\frac{2*log_53}{log_53}=2.$

$e)~2*log_34-4*log_32=log_34^2-log_32^4=log_316-log_316=0$

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