Question

Ştie cineva la subiectul al 3-lea ? Dau coroana si puncte in plus celui mai bun!!

Answer 1

a) x→-2 limf(x)=(x²-x-1)/(x+1)=[(-2)²-(-2)-1]/(-2+1)=5/(-1)=-5
b) x→-∞ limf(x)/(x²-x-1)=lim(x²-x-1)/(x+1)*1/(x²-x-1)=lim 1/(x+1)=1/(-∞+1)=0
c)Asimptota y=mx+n
  m=lim  f(x)/x=(x²-x-1)/x*(x+1)=1  x→-∞

n=lim(f(x)-mx)= lim[(x²-x-1)/(x+1)-x]=lim(x²-x-1-x²-x)/(x+1)=lim(-2x)/(x+1)=-2  pt  x→-∞
y=x-2
2a)f(x)={3x+2   x>1
{2^x+1  x≤1
f(3)=3*3+2=11
f(0)=2^0+1=1+1=2
f(3)-f(0)=11-2=9
b)  nu se   vede bine
c)x→-∞  lim2f(x)=2limf(x)=2*lim(2^x+1)=2*lim(2^(-∞)+1)=2*(0+1)=2