Question

Stie cineva sa rezolve o asfel de problema ?

Answer 1

GF=1725-820-410=495

TFA
ΔCED≈ΔCBA
CE/CB=ED/1080
(410+495)/1725=ED/1080
 ED=905*1080:1725≈566,61


TFA
ΔCGF≈ΔCBA

CG/CB=GF/BA
495/1725=GF/1080
GF=495*1080/1725≈309,91
obs
puteaudf fi lasate si ca fractii rationale ireductibile...dar n-am mai simplificat, am facut pe cal;culator

Answer 2

notam CG=x=1725-410-820=495
cu teorema fundamentala a asemanarii putem scrie:
x/(1230+x)=FG/1080
FG=495*1080/(1230+495)
FG=7128/23

(410+x)/(1230+x)=DE/1080
DE=905*1080/1725
DE=13032/23