Question

Stiind că a =100- (7 la puterea a 2 + 3 la puterea a 3 ) si b=25 la puterea a 4 :5 la puterea a 8, calculează b la puterea a

Answer 1

a=100-($7^{2}$+$3^{3}$)
a=100-(49+27)
a=100-76
a=24

b=$25^{4}$:$5^{8}$
b=$(5^{2} )^4$:$5^{8}$
b=$5^{8}$:$5^{8}$
b=1

$b^{a}$=$1^{24}$=1

Answer 2

a=100-(49+27)
a=100-66
a=34

b=(5²)⁴:5⁸
b=5⁸:5⁸
b=1
bᵃ=1³⁴
bᵃ=1