Question

Stiind ca a=100-(7la puterea 2 +  3 la puterea 3) si b=25 la puterea 4 : la 5 la puterea 8 , calculati b la puterea a

Answer 1

a=100-(49+27)=24
$b= 25^{4} : 5^{8} =( 5^{2} ) ^{4} :5^{8}=5^{8}:5^{8}=1$
$b^{a} =1 ^{24} =1$