Question

stiind ca a +b =46si b + c = 28 calculeaza socolelile 2a+3b+c=,a+2b+c= ,a+4b+3c=

Answer 1

a+b = 46
b+c = 28
2a+3b+c = (2a+2b)+(b+c) = 2*(a+b)+(b+c) = 2*46+28 = 92+28 = 120
a+2b+c = (a+b)+(b+c) = 46+28 = 74
a+4b+3c = (a+b)+(3b+3c) = (a+b)+3*(b+c) = 46+3*28 = 46+84 = 130