Question

Stiind ca ab+bc=32 si b (3+a+c)=44, sa se afle media aritmetica a numerelor a,b si c.
Urgent! Dau 30 puncte!

Answer 1

ab+ac=32
b(3+a+c)=44
(ab+bc)-b(3+a+c)
ab+bc-3b+ab+bc
3b=44-32
3b=12
b=4
 
b(3+a+c)=44
4(3+a+c)=44
12+4a+4c=44
4a+4c=32/4
a+c=8

M=(A+B+C):3
M=(8+4):3
m=12:3
m=4

Answer 2

ab + bc = 32 

b ( 3 + a + c ) = 44 
3 b + ab + bc = 44 
3 b + 32 = 44 
3 b = 44 - 32 
3 b = 12 
b = 12 : 3 
b = 4 

b× ( 3 + a + c ) = 44 
4 × ( 3 + a + c ) = 44 
a + c = 44 : 4 - 3 = 11 - 3 = 8 

Ma = ( a + b + c ) : 3 = ( a + c + b ) : 3 = ( 8 + 4 ) : 3= 12 : 3 = 4 →media aritmetica a celor trei numere