Question

stiind ca ac-bc+3c=3293 si c=89,unde a,b,c, apartine N,nr. a-b este egal cu:
a)40 b)34 c)3201 d)37

Answer 1

ac-bc+3c=3293

c=89

a-b=?

a x 89-b x 89+3 x 89=89a-89b+267=3293

89a-89b=3026

a-b=3026:89

a-b=34

deci Raspunsul este egal cu:b)34

Answer 2

3·89=267;
⇒ac-bc=3293-267
⇒ac-bc=3026
⇒c[a-b]=3026
⇒a-b=3026/89
⇒a-b=34⇒b.