Question

Stiind că dublul sumei a două numere impare consecutive este 1.312 ,numerele sunt:

Answer 1

(a+a+2)×2=1312
2a+2a+4=1312
4a=1308
a=327
a+2=379

Answer 2

a;b=> nr.impare consecutive =>b=a+1
(a+b)*2=1312
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a=?b=?

a+a+2=1312:2
(2a+2a+2)*2=1312
4a+4=1312
4a=1312-4
a=1308:4
a=327
b=327+2
b=329

(327+329)*2=1312
656*2=1312
1312=1312