Question

Stiind ca intre termenii unei scaderi exista relatia d+s+r=8000, ce valori poate lua a din inegalitatea: 7333 ≤ d+ aaaa < 10 000?

Answer 1

d+s+r=8000
d=s+r

2d=8000

d=4000

7333<4000+aaaa<10000 l -4000

3333<aaaa<6000

aaaa={4444;5555}