Question

Stiind ca numerele x,y sunt invers proportionale cu 1/2 si 1/3 aflativaloarea raportului (10x-y)/(7x-4y)

Answer 1

x*1/2=k  x=2k
y*1/3=k  y=3k
(10x-y)/(7x-4y)=(10*2k-3k)/(7*2k-4*3k)=17k/(14k-12k)=17/2

Answer 2

(x;y) i.p.(1/2 ; 1/3) <=>    x/2=y/3= k  
                             deci  x=2k si  y=3k ,
$\frac{10x-y}{7x-4y}= \frac{20k-3k}{14k-12k}=\frac{17k}{2k}=17/2=8,5\;\;$