Question

Stiind ca s-au folosit 24 g H si 568 g Cl, calculeaza masa de substanta in exces si cantitatea de HCl obtinuta.

Answer 1

Scriem ecuatia: H2 + Cl2 -> 2HCl
se observa ca la 1mol de H2 avem 1 mol de Cl2
transformam masele in moli
nH2=mH2/MH2=24/2=12moli
nCl2=mCl2/MCl2=568/71=8moli
cum 12>8 => H2 e in exces
avem 4 moli de exces
m=n*M=4*2=8g H2
........1mol...2*36,5g
H2 + Cl2 -> 2HCl
........8moli..x=?
x=8*73=584g HCl