Question

stiind ca substanta sulfat de fier,are formula chimica FeSO4 determinati
-raportul de masa si compozitia procentuala
se dau AFe=56 , AS = 32 AO=16
URGENTTTTT!!!!!!!!

Answer 1

FeSO4

raport de masa=r . m.

r. m .=AFe : A S: 4AO=56: 32 : 4.16=56 : 32: 64 =7  : 4  :8

Comp. procentuala prin masa moleculara

M=56 + 32 +64=152 ----->1 mol=152 g

152g FeSO4--------56 g Fe--------32g S-----------64 g O

100 g-----------------------x---------------y-------------------z

x=100 .56:152=36,84 la suta Fe

y=100.32:152=

z=100.64:152=

Continua !