Question

Stiind ca tangent de x e egal cu 1/2, x e numar real aflati cat face tangent( x+pi/3) va rog frumos.

Answer 1

tg(a+b)=$\frac{tga+tgb}{1-tgatgb}$.
Deci tg(x+π/3)=$\frac{tgx+tg \frac{ \pi}{3} }{1-tgxtg \frac{ \pi}{3}} = \frac{ \frac{1}{2} + \sqrt{3} }{1- \frac{ \sqrt{3} }{2} }= \frac{1+2 \sqrt{3} }{2- \sqrt{3}}=8+ 5\sqrt{3}$, dupa ce rationalizam numitorul, amplificand fractia cu 2+√3.

Answer 2

Rezolvare o gasesti in poză