Question

Știind ca x=23 și y+z=41,calculați: a) 3x+2y+2z b) 5x+3y+3z c) 8x+5y+5z d) 4y+4z-5x e) 7z+7y-9x f) 9y+9z+7x

Answer 1

x = 23  si  y + z = 41

a)   3 x + 2 y + 2 z =  151

= 3 × 23 + 2 × ( y + z ) = 69 + 2 × 41 = 69 + 82 = 151

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b)   5 x + 3 y + 3 z = 238

= 5 × 23 + 3 × ( y + z ) = 115 + 3 × 41 = 115 + 123 = 238

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c)   8 x + 5 y + 5 z = 389

8 × 23 + 5 × ( y + z ) = 184 + 5 × 41 = 184 + 205 = 389

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d)   4 y + 4 z - 5 x = 49

= 4 × ( y + z ) - 5 × 23 = 4 × 41 - 115 = 164 - 115 = 49

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e)    7 z + 7 y - 9 x = 80

= 7 × ( y + z ) - 9 × 23 = 7 × 41 - 207 = 287 - 207 = 80

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f)    9 y + 9 z + 7 x = 530

= 9 × ( y + z ) + 7 × 23 = 9 × 41 + 161  = 369 + 161 = 530