Question

stiind ca x+4*y+2*z=13 si 3*x + 2* z=11 determinati x+y+z

Answer 1

x + 4*y + 2*z=13  si

3*x +      + 2*z=11    le adunam si obtinem...

4x  +  4y  +  4z = 24   | :4

x  +  y  + z = 24 : 4 = 6

Answer 2

X+4y+2z= 13

3x+2z= 11

(X+4y+2z) + ( 3x+2z) = 13+11 =

=> 4x+ 4y+ 4z= 24

4×( x+y+z)= 24

X+y+z= 24:4= 6

X+y+z= 6