Question

Stiind ca x=5 si y+z= 14 ,calculcati:
a) x+2y+2z
b) 5x+3y+ 3z

Answer 1

x=5
y+z= 14

a) x+2y+2z = x+2(y+z)=5+2*14=5+28=33

b) 5x+3y+ 3z=5x+3(y+z)=5*5+3*14=25+42=67

Answer 2

$x=5 \\ y+z=14 \\ a).x+2y+2z=x+2(y+z)=5+2 \cdot 14=5+28=33 \\ b).5x+3y+3z=5x+3(y+z)=5 \cdot 5+3 \cdot 14=25+42=67$