Question

Stiind ca x+y=3 si ax+ay+bx+by=√27,calculati a+b.

Answer 1

ax+ay+xb+by=a(a+y)+b(x+y)
Cum x+y=3 => 3a+3b=$\sqrt{27}$ <=> 3(a+b)=3$\sqrt{3}$ => a+b=$\sqrt{3}$

Answer 2

ax+ay+bx+by=√27x(a+b)+y(a+b)=√27
(a+b)(x+y)=3√3
(a+b)*3=3√3
a+b=3√3:3
a+b=√3