Question

stiind ca x+y+z=61 si 2x+3y+4z=205,calculati produsul (2x+y)(2z+y)(z-x)

Answer 1

Răspuns

2x + 3y + 4z = 205

2x +2y + 2z+ y + 2z = 205

2 ( x + y + z )+ y +2z = 205

2 * 61 + y + 2z = 205

y + 2z = 205 -122

y + 2z = 83

2x + 3y + 4z = 205

2x + y + 2y + 2z +2z = 205

2x + y + (y + 2z) + (y + 2z) = 205

2x + y + 2(y + 2z) = 205

2x + y +2*83 = 205

2x + y = 205 - 166

2x + y = 39

x + y + z = 61

2x - x + y + z = 61

2x + y + z - x = 61

39 + z - x = 61

z - x = 61 - 39

z - x =22

(2x + y) (2z + y) (z - x) = 39 * 83 * 22 = 71214

Explicație pas cu pas: