Question

stiind ca xy+yz=320 si x+z=16 aflati numarul natural y

Answer 1

xy+yz= 320
x+z = 16

y(x+z) = 320
16y = 320
y = 320/16
y = 20

Answer 2

y(x+z)=320
y×16=320
y=320:16
y=20