Question

Subleciul al II-lea SU ILUL 1. a) Efectuați 4,15+ [22,5:1,5.0,4-(33,6:3·2-4,22)];​

Answer 1

Salut!

Efectuati:

4,15+ [22,5:1,5*0,4-(33,6:3*2-4,22)]=

=4,15+[22,5:1,5*0,4-(22,4-4,22)]

=4,15+(22,5:1,5*0,4-18,18)

=4,15+(6-18,18)

=4,15-12,18

=-8,03

Succes!

Answer 2

Răspuns:

-8,03

Explicație pas cu pas:

4,15+[22,5:1,5×0,4-(33,6:3×2-4,22)]=

4,15+[15×0,4-(11,2×2-4,22)]=

4,15+[6-(22,4-4,22)]=

4,15+(6-18,18)=

4,15+(-12,18)=

4,15-12,18=

-8,03