Question

subpunctele încercuite pls

Answer 1

Aplic produsul mezilor= produsul extremilor.

c)
(x+2)*(x+4)= (x-3)*(x-5)
x²+6x+8= x²-8x+15
x²-x²+6x+8x=15-8
14x=7
x=7/14
x=1/2

d) x/ (5-4√3) = (5+4√3)/2
(5-4√2)(5+4√2)= 2x
25- 16*2= 2x
25-32= 2x
2x= -7
x= -7/2

e)
[x(√3-1)-√3(√3+1)] /  √3*(√3-1) = (√3-1)/( √3+1)

(√3+1)*(x√3- x-3-√3)= √3 *(√3-1)²
3x-x√3 -3√3 -3 + x√3- x -3-√3=√3( 3-2√3+1)
2x-4√3-6= 4√3-6
2x=8√3-12  | :2
x=4√3- 6


La f. nu mai stiu cum se face.