Question

Subpunctul b) chiar nu stiu sa îl fac ma puteți ajuta?

Answer 1

b) (√2-√5)/√10+(√6-√3)/2√3-(2-√5)/2√5 rationalizam cu √10 prima fractie, apoi cu √3 si √5
(√20-√50)/10+(√18-√9)/6-(2√5-√25)/10=(2√5-5√2)/10+(3√2-3)/6-(2√5-5)/10=(-5√2-5)/10+(3√2-3)/6 amplificam prima fractie cu 3 si cealalta cu 5
(-15√2-15)/30+(15√2-15)/30= -30/30= -1

Answer 2

b) √2-√5/√10 + √6-√3/√12 - 2-√5/√20 = 
(√2-√5)√10/10 + √6-√3/2√3  - 2√5/2√5 = 
√20-√50/10 + √6-√3/2√3 - (2-√5)√5/10 = 
2√5-5√2-2√5+5/10 + √18-3/6 =
5(-√2+1)/20 + 3√2-3/6 = 
-√2+1/2 + 3(√2-1)/6 =
-√2+1+√2-1/2 =
0/2 =0