Question

Sulfura de hidrogen arde in exces de oxigen, formand oxid de sulf (IV) si apa. Calculati volumul de SO2 (c.n), care se formeaza la arderea a:
a)4 mol H2S; b)22,4l H2S (c.n); c)3,4g H2S.

Answer 1

2H2S+3O2=2SO2+2H2O .din reactie : din 2 moli H2S rezulta 2 moli SO2=> a) 4 moli H2S=>4moli SO2.VSO2=n ×Vm=4 moli×22.4L=89.6 L
b) nH2S=V /V m=22.4L ÷22.4L=1 => un mol de H2S .1 mol H2S=>1 mol SO2=>VSO2=1 mol×22.4 L=22.4L
c)nH2S =m H2S/MH2S
M H2S=2×A H+A S=2+32=34g
nH2S=3.4g÷34g= O.1 moli H2S.
O.1 moli H2S=>O.1 moli SO2 .
V SO2=n SO2 ×V m=0.1×22.4=2.24L