Question

Suma a 10 numere naturale impare distincte este 100.Aflati numerele urgent!!!

Answer 1

(n+1)+(n+3)+(n+5)+(n+7)+(n+9)+(n+11)+(n+13)+(n+15)+(n+17)+(n+19)=100
10n+(1+3+5+7+9+11+13+15+17+19)=100
10n=100-(1+3+5+7+9+11+13+15+17+19)
10n=100-100
n=0
atunci numerele vor fi
(n+1)+(n+3)+(n+5)+(n+7)+(n+9)+(n+11)+(n+13)+(n+15)+(n+17)+(n+19)
atunci numerele vor fi :
(n+1)=0+1=1
(n+3)=0+3=3
(n+5)=0+5=5
(n+7)=0+7=7
(n+9)=0+9=9
(n+11)=11
(n+13)=13
(n+15)=15
(n+17)=17
(n+19)=19
(1,3,5,7,9,11,13,15,17,19)