Question

suma a 10 numere naturale impare distincte este 100 aflați numerele plsssss ajutati ma dau coroanaaaa si fallow Plsss repedeeee​

Answer 1

Răspuns:

(n+1)+(n+3)+(n+5)+(n+7)+(n+9)+(n+11)+(n+13)+(n+15)+(n+17)+(n+19)=100

10n+(1+3+5+7+9+11+13+15+17+19)=100

10n=100-(1+3+5+7+9+11+13+15+17+19)

10n=100-100

n=0

atunci numerele vor fi

(n+1)+(n+3)+(n+5)+(n+7)+(n+9)+(n+11)+(n+13)+(n+15)+(n+17)+(n+19)

atunci numerele vor fi :

(n+1)=0+1=1

(n+3)=0+3=3

(n+5)=0+5=5

(n+7)=0+7=7

(n+9)=0+9=9

(n+11)=11

(n+13)=13

(n+15)=15

(n+17)=17

(n+19)=19

(1,3,5,7,9,11,13,15,17,19)