Question

Suma a 3 nr este 104,28.Daca din fiecare se scade acelasi nr natural,se obtin nr 19,57 19,89 19,82.Determinati nr!

Answer 1

a+b+c=104,28
a-x=19,57
b-x=19,89
c-x=19,82
19,57+19,89+19,82+x+x+x=104,28
59,28+3x=104,28
3x=104,28-59,28
3x=45
x=45:3
x=15
a-15=19,57
a=19,57+15
a=34,57
b-15=19,89
b=19,89+15
b=34,89
c-15=19,82
c=19,82+15
c=34,82