Question

"suma a 3 nr este 227. daca din fiecare se scade acelasi nr se obtin nr 122,38,47"

Answer 1

a+b+c = 227 a-x=122 -> a = 122+x b-x=38 -> b = 38+x c-x=47 -> c = 47+x 122+x+38+x+47+x=227 207+3x=227 3x=20 -> x=20/3 -> a = 122+20/3=(366+20)/3=386/3 b = 38+20/3=(114+20)/3=134/3 c = 47+20/3=(141+20)/3=161/3 (386+134+161)/3=227 Sper ca te-am ajutat :)