Question

suma a 3 nr este 314 aflați cele 3 nr dacă primul reprezinta 14%din al 2 Lea nr iar al 2 Lea reprezinta 50%din al 3 lea

Answer 1

$x + y + z = 314 \\ x = \frac{14}{100} \times y \\ y = \frac{ z}{2} = > z = 2y \\ \frac{14}{100} \times y + y + 2y = 314 \\ \frac{14y + 100y + 200y}{100} = 314 \\ y = \frac{314 \times 100}{314} = 100 \\ x = 14 \\ z = 200$

Answer 2

A+b+c= 314

A= 14×b/100 = 7b/50

b= 50×C/100 = C/2

C= 2b

A+b+c=. 7b/50 + b + 2b= 314

7b+ 50b + 100b= 314 ×50

157b= 15700

b= 15700÷157= 100

A= 7×100/50= 7×2 = 14

C= 2×100 200

Proba ?

14+100+200= 314 !