Question

Suma a 3 nr. natural consecutive este 219.Aflati cele 3 nr.

Answer 1

$a+b+c=219 \\ a+(a+1)+(a+2)=219 \\ 3a+3=219 \\ 3a=216 \\ a=72 \\ b=a+1=72+1=73 \\ c=a+2=72+2=74$

Answer 2

a+a+1+a+2=219
3a=219-3
3a=216
a=72
nr : 72,73,74