Question

Suma a 3 nr naturale este 427.Daca adunam la cele 3 nr 3 nr naturale
consecutive,obtinem 41,89,321.
Afla numerele.
va rog ajutatima va dau 10 puncte

Answer 1

a+b+c = 427
a+X = 41 =>a = 41-X
b+X+1 = 89 => b = 89 -1-X = 88-X
c+X+2 = 321 => c = 321-2-X = 319-X
41-X + 88-X + 319-X = 427
3×X = 448-427
3×X = 21
X = 21:3
X = 7

a = 41-7 = 34
b = 88-7 = 81
c = 319-7 = 312

34+81+312 = 427

a = 34
b = 81
c = 312