Question

SUMA A 3 NR. NATURALE PARE CONSECUTIVE ESTE 252.CARE SUNT NR?

Answer 1

k-2+k+k+2=252
3k=252
k=252/3
k=84
k-2=84-2
k=82
k+2=84+2
k=86

Answer 2

Salut,


Notam numerele astfel: x, x + 2, x + 4.

x + x + 2 + x + 4 = 252 <=> 3x + 6 = 252 <=> 3x = 252 – 6 <=> 3x = 246 <=> x = 246 : 3 <=> x = 82

x = 82

x + 2 = 82 + 2 <=> x + 2 = 84

x + 4 = 82 + 4 <=> x + 4 = 86

Numerele cerute sunt: 82, 84, 86.



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252 – (2 + 4) = 252 – 6 = 246 (3 parti egale cu numarul mic)

246 : 3 = 82 (primul numar)

82 + 2 = 84 (al doilea numar)

82 + 4 = 86 (al treilea numar)

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