Question

suma a 3 numere consecutive impare este 57. aflati numerele.. Va rog.

Answer 1

a+b+c =57
b=a+2
c=a+4
a+a+2+a+4=57
3a+2+4=57
3a+2=57-4
3a+2=53
3a=53-2
3a=51
a=51:3
a=17

b=17+2
b=19

c=17+4
c=21
V:17+19+21=57

Answer 2

Rezolvarea:

a+b+c+57
a+(a+1)+(a+2)=57

Desfiintam parantezele:

a+a+1+a+2=57

Calculam:
3a=57-1-2
3a=54

Aflam a-ul:

a=54:3
a=18

Aflam celelalte necunoscute:
b=a+1
b=18+1
b=19

c=a+2
c=18+2
c=20

Verificam:
18+19+20=57

Sper ca te-am ajutat :D