Question

suma a 3 numere este 1000.daca se scade din fiecare,acelasi nr se obtin nr 278,246 si134

Answer 1

a + b + c = 1000

a - x = 278 => a = 278 + x 

b - x = 246 => b = 246 + x

c - x = 134 => c = 134 + x

278 + x + 246 + x + 134 + x = 1000

3x = 1000 - 658

3x = 342

x = 342 : 3

x = 114

a = 278 + 114

a = 392

b = 246 + 114

b = 360

c = 134 + 114

c = 248

Answer 2

a+b+c= 1000
a-x=278 ⇒ a=278+x
b-x =246 ⇒b=246+x
c-x =134 ⇒c=134+x
278+x+246+x+134+x=1000
3x+658=1000
3x= 1000-658
3x=342
x=114
a=278+114
a=392
b=246+114
b=360
c=134+114
c=248
V:a+b+c= 392+360+248=1000(adevarat)