Question

Suma a 3 numere este 18, sa se afle numerele stiind ca diferenta primelor doua este egala cu suma ultimelor doua. Va rog, dau coronita.

Answer 1

18:3=6(a)
18:3=6(b)
18:3=6(c)

Answer 2

a+b+c=18;
⇒a-b=b+c;
⇒a=b+b+c⇒a=2b+c;
⇒2b+c+b+c=18
⇒3b+2c=18
⇒b=4⇒c=3;⇒a=2·4+3=8+3=11;
⇒b=6⇒c=0;⇒a=2·6+0=12+0=12;
⇒a,b,c∈[[4,3,11],[6,0,12],[2,6,10],[0,9,9]];
⇒b=2⇒c=6;⇒a=2·2+6=4+6=10;
⇒b=0⇒c=9;⇒a=2·0+9=0+9=9;