Question

suma a 3 numere este 184528.Suma primelor doua nr este 123312,iar diferenta ultimelor doua numere este 16452.Care sunt nr
nr=numere

Answer 1

x+y+z=184.528
x+y=123.312    deci  123.312+z=184.528   z=184.528-123.312=61.216

y-z=16.452  y-61.216=16.452  y=16.452+61.216=77.668

y=77.668
z=61.216 
x+77.668+61.216=184.528  x=184.528-61.216-77.668=45.644

Answer 2

a+b+c=184528
a+b=123312
b-c=16452
123312+c=184528
c=184528-123312
c=61216
b-61216=16452
b=16452+61216
b=77668
a+77668=123312
a=123312-77668
a=45644