Question

suma a 3 numere este 186.Scazand al treilea numar din suma a primelor doua obtinem 50.Scazand primul numar din suma ultimelor doua numere obtinem 36.Aflati cele trei numere.

Answer 1

a+b+c=186
(a+b)-c=50 ⇒ a+b=50+c
(b+c)-a=36 ⇒ b+c=36+a
50+c+c=186
2c=186-50
2c=136
c=136:2
c=68
a+36+a=186
2a=186-36
2a=150
a=150:2
a=75
75+b+68=168
b=168-75-68
b=25
V: 75+25+68=168

Answer 2

a+b+c=186
a9a+b)-c=50  ;  a+b=50+c
(b+c)-a =36
b+c =36+a
36+4  +c  =186
2c =186-50
2c =136
c =68
b+c =36+a
b+68 =36+118-b
b+b36+118-68
2b =86
b =43
a+b-c =50
a+b-68 =50
a+b =50+68=118
a=118-b 
a=118-43
a=75
 verif  ;   75+43+68 =186